# In any abc , find sina + sinb + sinc

Prove that an 3a = an 3b = an 3c if sin a + sin b + sin c = 0 & cos a + cos b + cos c = 0
https://math.stackexchange.com/questions/2015438/prove-that-tan-3a-tan-3b-tan-3c-if-sin-a-sin-b-sin-c-0-and
By geometry : (cos a,sin a),(cos b,sin b),(cos c,sin c) are three unit vectors which sum to lớn zero. Then they must be the vertices of an equilateral triangle inscribed in the trigonometric ...

Bạn đang xem: In any abc , find sina + sinb + sinc

https://math.stackexchange.com/questions/2651583/finding-relationships-between-angles-a-b-and-c-when-sin-a-sin-b-sin-c
If we plot a vector (or complex number) sketch in which sin alpha = sin eta + sin gamma as follows we can establish some interesting consequential relations. One is given by the length of ...
Let p = fracx^2x^2 + k, quad q = fracy^2y^2 + k, quad r = fracz^2z^2 + k. Then by assumption p + q + r = 1. Letting a, b và c be the sides of the triangle, we have by ...

Xem thêm: Nguyên Nhân Bùng Nổ Dân Số Ở Việt Nam, Nguyên Nhân, Hậu Quả Và Cách Giải Quyết

Is there an elegant way to prove that the sequence sin (n)\_n in mathbfN lies dense in <-1, 1> subset mathbfR?
https://www.quora.com/Is-there-an-elegant-way-to-prove-that-the-sequence-sin-n-_-n-in-mathbf-N-lies-dense-in-1-1-subset-mathbf-R
I would vì chưng that : 1 - subgroups of (R,+) are of the size a Z or dense in R. Và that a Z + b Z = c Z is equivalent to lớn a/b is rational. 2 - given a surjective và continuous function f, from I ...

Xem thêm: Tìm Phân Số Có Tổng Tử Số Và Mẫu Số Bằng 25 Mẫu Số Lớn Hơn Tử Số 7 Đơn Vị ?

This is the definition of sine law which state that fracasin left( A ight) =fracbsin left( B ight) =fraccsin left( C ight) =2R where R is the circumradius of the ...
It seems that it follows from Jordan's inequality . frac2pi(A + B +C) = 2 le sin(A) + sin (B) + sin (C)
More Items     left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 và 3 \ -1 và 1 & 5 endarray ight>      EnglishDeutschEspañolFrançaisItalianoPortuguêsРусский简体中文繁體中文Bahasa MelayuBahasa Indonesiaالعربية日本語TürkçePolskiעבריתČeštinaNederlandsMagyar Nyelv한국어SlovenčinaไทยελληνικάRomânăTiếng Việtहिन्दीঅসমীয়াবাংলাગુજરાતીಕನ್ನಡकोंकणीമലയാളംमराठीଓଡ଼ିଆਪੰਜਾਬੀதமிழ்తెలుగు